If it's not what You are looking for type in the equation solver your own equation and let us solve it.
3z^2-5z-12=0
a = 3; b = -5; c = -12;
Δ = b2-4ac
Δ = -52-4·3·(-12)
Δ = 169
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{169}=13$$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-13}{2*3}=\frac{-8}{6} =-1+1/3 $$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+13}{2*3}=\frac{18}{6} =3 $
| X^2-11x+72=0 | | 3x=30x-x | | 7=9-3n | | 4x+41+49=180 | | 16x*x*x-200x=5 | | .8a–5+2a–6+18=9+8–3a+13a–10 | | 4.5x3.5x2=31.5 | | 7(3x+4)=9(6x+7)+8 | | 3.2(x+4)+2^2+1.7(x-3)=27 | | n+(n+36)=49 | | 4-2/3y=-2 | | -7(5x-1)+2=-35x+9 | | -6r=2=-9r=2=3r | | 6w+7/4=w+6/4-6 | | 8y-42=3y-27 | | -7y-8=8y+22 | | 20+c=-20-11c-20 | | X+x/3=10 | | X/5-1=x+7 | | |4+7x|=-2 | | 4r-4=-36 | | 20/2^2=h+1 | | n-7/9=1/6 | | 2h-9=5 | | x=7*(9x^2-5x+8) | | 180-x=59x | | 8.8+p=-7.4 | | 3e-7=8 | | (4−-5)=−3-5+b | | 8/10=10/x | | (X+5)+x=19 | | 12x^2+64=64x |